relativity of motion :
Interestingly, from an external frame of reference, 0 is stationary.
But from the point of view of either A or B, 0 is receding from them at the speed of light!
And A and B are separating (i.e. the space/distance between A and B is expanding/increasing)at twice the speed of light!
So motion is relative to one's observational frame of reference.
If O is tbe point of origin of the universe and the maximum velocity of the Big Bang wave front was "c" (assuming that the wave front generated by the Big Bang propogated outward in all directions at the maximum allowable speed) ,
then A and B represent the outer boundaries of an expanding sphere.
The distance between A and B is the diameter of the universe wch is expanding at a maximal velocity of 600,000 km/second.
Accepting that the universe is 13.7 billion years old(13.7 billion years to zero time) we can calculate the number of seconds in 13.7 billion years =X seconds*.
Since the diameter of the universe is expanding at 600,000km each second,
the present diameter of the universe is: 600,000km x X seconds* =
13.
7 billion years x 31,536,000 s/ year = 13.7 x 10^9 years x 31,536 x10^3 s/year= 4,320,43.2 x10^12 seconds
6x10^5km/s x 4,320,432 x10^11s = 25,922,592 x 10^16 km = 2.6 x 10^23 km
*How many seconds in a year:
60 s/minute
60 minutes/ hr
3600 s/hour
24 hr/day
86400s/day
365 days/ year
31,536,000 s/ year
***************************************
In one year light travels 9.5 x10^12 km
In 13.7 x 10^9 years it will have travelled 130.15 x 10^21 km =1.3 x 10^23 km
radius of universe = 1.3 x 10^23 km
diameter = 2.6 x 10^23 km
*****/*******************************
V=d/t. (velocity =distance/time )
v=c= maximum allowable velocity of expansion.
d= distance from point of origin to outer edge or boundary = radius of universe
t= 13.7 billion years(time from t=0 to now)
d=vt
v= c=9.5x 10^12 km/year
d=9.5x 10^12 km/year X 13.7 x10^9years =130 x10^21 km =1.3 x 10^23 km (this is the radius from center to outer edge, and the maximum distance light has travelled in 13.7 billion years)
Hence diameter = 2r= 2.6 x 10^23 km
If the universe has a finite age, diameter and volume....what is outside the universe? That is, what is it expanding into? Emptiness?
ReplyDeleteWhat is the Source of the energy that generated and makes up the universe?
Dems the ?!
DeleteMy purely theoretical calculation is based on the simplistic assumption that the universe has always expanded at the same maximum velocity of 2C (600,000 km/sec)throughout its history.
ReplyDeleteBut recent evidence indicates that the expansion velocity is not constant but accelerating.
In other words the velocity of expansion originally was much lower than it is now.
What is the present expansion rate of the universe? (Hubble Constant)
Estimates of the age of the universe is contingent upon the estimate of the expansion velocity.
There is also tbe assumption tbat tbe outer delimiting boundary of cosmic space cannot expand or propogate outward from its point of origin faster tban light speed.
DeleteThis speed limit may apply only to objects trav eling tbrough space, but not to space itzelf.
In other words, the laws of physics do not e x clude tbe possibity tbat space itself may expand at greater tban tbe speed of light.
Indepth discussion at this site:
ReplyDeletehttp://curious.astro.cornell.edu/question.php?number=575
Do these questions make sense:
ReplyDeleteAre tbere parts of tbe universe so distant from us as to be unobservable by virtue of the fact that insufficient time has passed for light from those places to have reached us?
How much of the ligbt of the universe has passed us by because we did not yet exist to receive/observe it?
13.7 billion light years =1.29609239 × 10^23kilometers
ReplyDeleteThe size and tbe age of ybe univefse is bryond human understanding
ReplyDelete--carl sagan
Given this maximum diameter and a spherical shape...and assuming an average mass density,
ReplyDeleteit would be possible to calculate
the total mass/energy content of the universe.