units of energy = units of mass
The newton is the unit of force derived in the SI system; it is equal to the amount of force required to accelerate a mass of one kilogram at a rate of one meter per second per second. In dimensional analysis, F=ma, multiplying m (kg) by a (m/s2), the dimension for 1 newton unit is therefore: 1N =1 kg·m/s²
energy is defined via work, the SI unit for energy is the same as the unit of work – the joule (J), named in honour of James Prescott Joule and his experiments on the mechanical equivalent of heat. In slightly more fundamental terms, 1 joule is equal to 1 newton-metre(the energy exerted by the force of one newton acting to move an object through a distance of one metre) and, in terms of SI base units:
1J = kg (m/s)^2 = 1 kg m2 s^−2,= (1 newton meter)
1 Joule = 6.24150974×10^18 eV
One joule in everyday life is approximately:
-the energy required to lift a small apple one meter straight up.
-the energy released when that same apple falls one meter to the ground.
Physicists commonly express the mass of fundamental particles in terms of their energy, but the energy unit used to do this is typically the electron volt (eV). 1eV = 1.60217646 * 10^ -19 joules (1 joule = 6.24150974 * 10^18 eV).
An energy unit that is used in atomic physics, particle physics and high energy physics is the electronvolt (eV).
One eV is equivalent to 1.60217653×10^−19 J.
1eV = 1.60217653×10^−19 J (Visible light has between 2 and 3 eV of energy per photon, and X-rays about 60,000 eV)
1Mev =10^6eV
1Gev =10^9eV (10^9 eV is the energy contained in a single proton at rest)
The energy of the most energetic gamma rays range between 10 to 100 GeV (ten billion to one hundred billion electron-volts per photon).Gamma rays are the most energetic form of light.
1TeV =10^12eV , or 1.602×10−7 J,
(The most-energetic known cosmic rays have an energy of 10^8 TeV)
The LHC slams beams of particles together at a collision energy of 7 TeV, or 7 million electron volts.(14 TeV: The 'Designed' collision energy of protons at the Large Hadron Collider.)The largest machine in the world (the LHC)can "see" particles that are 10^3 X smaller than a proton.Since the diameter of a proton is 2 × 10^-14 meters ,the LHC is a "microscope" that can detect particles down to 2 x 10^-17 meters in diameter.
By mass-energy equivalence, the electron volt is also a unit of mass.
It is common in particle physics, where mass and energy are often interchanged, to use eV/c2, where c is the speed of light in a vacuum
(from E = mc2). Even more common is to use a system of natural units and simply use eV, with c set to 1 as a unit of mass.
For example, an electron and a positron, each with a mass of 0.511 MeV/c2, can annihilate to yield 1.022 MeV of energy.
The proton has a mass of 0.938 GeV/c2, making a gigaelectronvolt (1Gev =10^9eV) a very convenient unit of mass for particle physics.
1 GeV/c2 = 1.783 × 10−27 kg
The atomic mass unit, 1 gram divided by Avogadro's number, is almost the mass of a hydrogen atom, which is mostly the mass of the proton. To convert to megaelectronvolts, use the formula:
1 amu = 931.46 MeV/c2 = 0.93146 GeV/c2
1 MeV/c2 = 1.074 × 10–3 amu
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
A coefficient is a constant or fixed number in front of a variable.
In the equation m = 1/c^2 x E (transposing E = mc^2)
1/c^2 is a coefficient equal to 1 / (the speed of light^2)
= 1/8.98755179 × 10^16 m^2 / s^2
= 0.111265006 × 10^16 s^2 / m^2
(error! see comment section)
= 1.11265006 × 10^15 s^2 / m^2
(error! see comment section)
If we write the equation E = mc^2 as E = c^2 m,
the coefficien c^2 =
(speed of light)^2 = 8.98755179 × 10^16 m^2 / s^2
Hence E= (8.98755179 × 10^16 m^2 / s^2 )x mass (in kg)
A proton at rest has a mass of 1.67 x 10^-27 kg.,
and this has the energy equivalence of 1 x 10^9 eV
Therefore 1 kg of protons has the energy equivalence of :
1 x 10^9 eV divided by 1.67 x 10^-27 kg
= 0.598802395 x 10^36 eV
=5.9 x 10^35 eV
(or converting eV to Joules):
Since 6.24150974×10^18 eV =1 joule,
5.9 x 10^35 eV = 5.9 x 10^35 eV /6.24150974×10^18 eV per joule
=0.94551 x 10^17 =9.45 x 10^16 joules
Therefore 1 kg of dirt (or anything) has the energy equivalence of 9.45 x 10^16 joules.
Since one megaton of TNT is defined as being equivalent to 4.184 × 10^15 J, , the energy equivalent of 1 kg of mass is approximately 21.5 megatons of TNT.(megaton of TNT = 4.184 × 10^15 J)
The "atomic bomb" detonated over Hiroshima in 1945 had an energy equivalent of between 13 and 18 kilotons of TNT (54 and 75 TJ)(kiloton of TNT = 4.184 × 10^12 J)
Hence the energy contained within 1 kg of any mass is 10,000 X greater than that released by the Hiroshima bomb!
But splitting a uranium atom (as in an atomic bomb)converts only 0.1 % of it's mass into energy,whereas mixing matter and antimatter is 100% efficient.
100 pounds of antimatter converted completely into energy would exceed the yield of all the world's nuclear weapons.
Another example: an electron has a rest mass of 9.10938188 * 10^-31 kilograms. It's rest mass expressed in electron volts is 9.1094*10^-31 kg * (2.998 *10^8 m/s)^2 * 6.242 *10^18 eV/J = 5.11*10^5 ev = 511 keV.
How many "joule-drops" of pure and perfect energy are you made of?
Hint: multiply your weight in kilograms by 9.45 x 10^16 joules
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
Yes,..."from dust unto dust" ;
but,...more importantly, "from light unto light"!
The newton is the unit of force derived in the SI system; it is equal to the amount of force required to accelerate a mass of one kilogram at a rate of one meter per second per second. In dimensional analysis, F=ma, multiplying m (kg) by a (m/s2), the dimension for 1 newton unit is therefore: 1N =1 kg·m/s²
energy is defined via work, the SI unit for energy is the same as the unit of work – the joule (J), named in honour of James Prescott Joule and his experiments on the mechanical equivalent of heat. In slightly more fundamental terms, 1 joule is equal to 1 newton-metre(the energy exerted by the force of one newton acting to move an object through a distance of one metre) and, in terms of SI base units:
1J = kg (m/s)^2 = 1 kg m2 s^−2,= (1 newton meter)
1 Joule = 6.24150974×10^18 eV
One joule in everyday life is approximately:
-the energy required to lift a small apple one meter straight up.
-the energy released when that same apple falls one meter to the ground.
Physicists commonly express the mass of fundamental particles in terms of their energy, but the energy unit used to do this is typically the electron volt (eV). 1eV = 1.60217646 * 10^ -19 joules (1 joule = 6.24150974 * 10^18 eV).
An energy unit that is used in atomic physics, particle physics and high energy physics is the electronvolt (eV).
One eV is equivalent to 1.60217653×10^−19 J.
1eV = 1.60217653×10^−19 J (Visible light has between 2 and 3 eV of energy per photon, and X-rays about 60,000 eV)
1Mev =10^6eV
1Gev =10^9eV (10^9 eV is the energy contained in a single proton at rest)
The energy of the most energetic gamma rays range between 10 to 100 GeV (ten billion to one hundred billion electron-volts per photon).Gamma rays are the most energetic form of light.
1TeV =10^12eV , or 1.602×10−7 J,
(The most-energetic known cosmic rays have an energy of 10^8 TeV)
The LHC slams beams of particles together at a collision energy of 7 TeV, or 7 million electron volts.(14 TeV: The 'Designed' collision energy of protons at the Large Hadron Collider.)The largest machine in the world (the LHC)can "see" particles that are 10^3 X smaller than a proton.Since the diameter of a proton is 2 × 10^-14 meters ,the LHC is a "microscope" that can detect particles down to 2 x 10^-17 meters in diameter.
By mass-energy equivalence, the electron volt is also a unit of mass.
It is common in particle physics, where mass and energy are often interchanged, to use eV/c2, where c is the speed of light in a vacuum
(from E = mc2). Even more common is to use a system of natural units and simply use eV, with c set to 1 as a unit of mass.
For example, an electron and a positron, each with a mass of 0.511 MeV/c2, can annihilate to yield 1.022 MeV of energy.
The proton has a mass of 0.938 GeV/c2, making a gigaelectronvolt (1Gev =10^9eV) a very convenient unit of mass for particle physics.
1 GeV/c2 = 1.783 × 10−27 kg
The atomic mass unit, 1 gram divided by Avogadro's number, is almost the mass of a hydrogen atom, which is mostly the mass of the proton. To convert to megaelectronvolts, use the formula:
1 amu = 931.46 MeV/c2 = 0.93146 GeV/c2
1 MeV/c2 = 1.074 × 10–3 amu
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
A coefficient is a constant or fixed number in front of a variable.
In the equation m = 1/c^2 x E (transposing E = mc^2)
1/c^2 is a coefficient equal to 1 / (the speed of light^2)
= 1/8.98755179 × 10^16 m^2 / s^2
= 0.111265006 × 10^16 s^2 / m^2
(error! see comment section)
= 1.11265006 × 10^15 s^2 / m^2
(error! see comment section)
If we write the equation E = mc^2 as E = c^2 m,
the coefficien c^2 =
(speed of light)^2 = 8.98755179 × 10^16 m^2 / s^2
Hence E= (8.98755179 × 10^16 m^2 / s^2 )x mass (in kg)
A proton at rest has a mass of 1.67 x 10^-27 kg.,
and this has the energy equivalence of 1 x 10^9 eV
Therefore 1 kg of protons has the energy equivalence of :
1 x 10^9 eV divided by 1.67 x 10^-27 kg
= 0.598802395 x 10^36 eV
=5.9 x 10^35 eV
(or converting eV to Joules):
Since 6.24150974×10^18 eV =1 joule,
5.9 x 10^35 eV = 5.9 x 10^35 eV /6.24150974×10^18 eV per joule
=0.94551 x 10^17 =9.45 x 10^16 joules
Therefore 1 kg of dirt (or anything) has the energy equivalence of 9.45 x 10^16 joules.
Since one megaton of TNT is defined as being equivalent to 4.184 × 10^15 J, , the energy equivalent of 1 kg of mass is approximately 21.5 megatons of TNT.(megaton of TNT = 4.184 × 10^15 J)
The "atomic bomb" detonated over Hiroshima in 1945 had an energy equivalent of between 13 and 18 kilotons of TNT (54 and 75 TJ)(kiloton of TNT = 4.184 × 10^12 J)
Hence the energy contained within 1 kg of any mass is 10,000 X greater than that released by the Hiroshima bomb!
But splitting a uranium atom (as in an atomic bomb)converts only 0.1 % of it's mass into energy,whereas mixing matter and antimatter is 100% efficient.
100 pounds of antimatter converted completely into energy would exceed the yield of all the world's nuclear weapons.
Another example: an electron has a rest mass of 9.10938188 * 10^-31 kilograms. It's rest mass expressed in electron volts is 9.1094*10^-31 kg * (2.998 *10^8 m/s)^2 * 6.242 *10^18 eV/J = 5.11*10^5 ev = 511 keV.
How many "joule-drops" of pure and perfect energy are you made of?
Hint: multiply your weight in kilograms by 9.45 x 10^16 joules
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
Yes,..."from dust unto dust" ;
but,...more importantly, "from light unto light"!
